DescriptionThe XR16V2550IM is designed as a high performance dual universal asynchronous receiver and transmitter (UART) with 16 bytes TX and RX FIFOs. The device operates from 2.25 to 3.6 volts with 5 Volt tolerant inputs and is pin-to-pin compatible to exar's ST16C2550 and XR16C2550. Typical app...
XR16V2550IM: DescriptionThe XR16V2550IM is designed as a high performance dual universal asynchronous receiver and transmitter (UART) with 16 bytes TX and RX FIFOs. The device operates from 2.25 to 3.6 volts wit...
SeekIC Buyer Protection PLUS - newly updated for 2013!
268 Transactions
All payment methods are secure and covered by SeekIC Buyer Protection PLUS.
The XR16V2550IM is designed as a high performance dual universal asynchronous receiver and transmitter (UART) with 16 bytes TX and RX FIFOs. The device operates from 2.25 to 3.6 volts with 5 Volt tolerant inputs and is pin-to-pin compatible to exar's ST16C2550 and XR16C2550. Typical applications include portable appliances, telecommunication network routers, ethernet network routers, cellular data devices, factory automation and process controls.
XR16V2550IM has seven features. (1)2.25 to 3.6 volt operation. (2)5 volt tolerant inputs. (3)Pin-to-pin compatible to ST16C2550, XR16C2550 and XR16L2550 in the 48-TQFP package. (4)Two independent UART channels. (5)Device identification and revision. (6)Crystal oscillator (up to 32MHz) or external clock (up to 64MHz) input. (7)48-TQFP and 32-QFN packages. That are all the main features.
Some absolute maximum ratings of XR16V2550IM have been concluded into several points as follow. (1)Its power supply range would be 4V. (2)Its voltage at any pin would be from GND-0.3V to 5.5V. (3)Its operating temperature range would be from -40°C to +85°C. (4)Its storage temperature range would be from -65°C to +150°C. (5)Its package dissipation would be 500mW. It should be noted that stresses above those listed in absolute maximum ratings may cause permanent damage to device.
Also some electrical characteristics of XR16V2550IM at limits 2.5V are concluded as follow. (1)Its clock input low level would be min -0.3V and max 0.4V. (2)Its clock input high level would be min 2.0V and max Vcc. (3)Its input low voltage would be min -0.3V and max 0.5V. (4)Its input high voltage would be min 1.8V and max 5.5V. (5)Its output low voltage would be max 0.4V. (6)Its output high voltage would be min 1.8V. (7)Its input low leakage current would be max +/-10uA. (8)Its input high leakage current would be max +/-10uA. And so on. If you have any question or suggestion or want to know more information please contact us for details. Thank you!