REPEATER_EMERGENCT_POWER_SUPPLY

Published:2009/7/12 23:06:00 Author:May | From:SeekIC

If your repeater needs emergency power, this circuit might do. Connect a 12-V storage battery, a relay, and a 0.5-Ω 50-W resistor as shown. Normally, the battery charges at a low rate (less than 1 A) through the 0.5-Ω resistor. When power fails, current can flow from the battery through the diode for a few milliseconds, until the relay drops out and closes the contacts, completely eliminating any voltage drop. If your repeater doesn't use a 13.8-V power supply, you could purchase a 2-A battery charger and connect a 0.5- to l-Ω resistor (50 W) in series with the battery. This will charge at approximately 1/2 A and maintain the battery.



Reprinted Url Of This Article:
http://www.seekic.com/circuit_diagram/Power_Supply_Circuit/REPEATER_EMERGENCT_POWER_SUPPLY.html

Print this Page | Comments | Reading(3)