Published:2012/11/1 22:34:00 Author:Ecco | Keyword: Dual LEDs , alternately flasher | From:SeekIC
It only uses four elements to constitute an interesting two-tube alternately flasher circuit. VD1 is one flashing light-emitting diode, VD2 uses ordinary light-emitting diode. The working process: VD1 work requires 5V, 30mA. When it gets power, VD1 gets conduction, and there is about 5V voltage adding the series VD2 and VD3, VD3 is the 6.2V zener diode, so VD3 does not work, then only the VD1 is bright; when VD1 is intermittent bright, the supply voltage is added on VD2, VD3 through R current limiting, so VD3 regulator tube works, the current flows through VD2.
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