Published:2011/7/5 20:30:00 Author:Lucas | Keyword: High output , voltage conversion, current conversion | From:SeekIC
The circuit uses the floating ±15V +250 V power supply to get load voltage which is greater than 2OOV. Input voltage U is 0 -lOV, which could be 0-1V divided by R1 and R2. It is assumed that Al inverting input voltage is -lV, the ground potential is a benchmark, the Al output is placed forward and VTl has base current flowing, so the output end voltage increases, then current f. = LV/R3 through the load. When I. R3 =- lV, the loop is stable, if R3 changes in the range of 0.1 - lOkΩ, it can be converted into the current with the range of lOmA to l0OμA .
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