Published:2011/7/8 3:21:00 Author:Fiona | Keyword: balance constant current output | From:SeekIC
Circuit Work
OP amplifiers A1 and A2 are to change the unipolar input circuit to a differential input circuit that the balance is good and change the 0 ~ 10V input to 0 ~ 1MA output (B = 10V, divided by R1, R2 , current is determined by the RO, RO = 5K, it is the resistance of the selected magnification), if R7 = R2, then the voltage generated at both ends of R7, R2 will be equal, namely:
If it is required to generate asymmetric waveform, as long as the R7 is not equal to R2, VC1 and VC2 can not be equal. It can also be used to generate the sawtooth.
OP mplifiers A3, A4 is a symmetrical circuit, respectively use +10 V and-10V as the base power, you can get I + = VC1/R11, I-= VC6/R12 constant current,change resistors R11 and R12's resistance or change V0 to do the current range switching.If R11 changes at 200Ω~2000Ωfor the unit with 10 times, VC1 = 1V, the circuit can get the constant current output that I + = 5MA, 500UA.
Figure A is the block diagram of unction generator waveform form part, the capacitor C is to constant current charge and discharge, it can produce a good linear triangular wave.
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