Published:2009/7/6 20:15:00 Author:May | From:SeekIC
The circuit doubles the frequency of a digital signal by operating on both signal edges. Each transition causes exclusive-OR gate IC1 to produce a pulse, which clocks flip-flop IC3 after propagating through buffers IC2C and IC2B. If you remove capacitor C1, the circuit produces narrow output pulses. By including C1, you can obtain a desired duty cycle for a given input frequency flN. The C1 value for an approximate 50% dutycycle is:
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